An open -ended U-tube of uniform cross-sectional area contains water (density `1.0 g//cm^(23)`) standing initially 20 cm from the bottom in each arm. An immiscible liquid of density `4.0 g//cm^(2)` is added to one arm until a layer 5 cm high forms, as shown in the figure above. What is the ratio `h_(2)//h_(1)` of the heights of the liquid in the two arms ?

Options

A. `3//1`
B. `5//2`
C. `2//1`
D. `3//2`

Answer

C

Explanation

`(h_(2))/(h_(1))=(20+10)/(5+10)" "implies (h_(2))/(h_(1))=(2)/(1)`