A cone of radius r and height r is under a liquid of density d.its base is parallel to the free surface of the liquid at a depth H from it as shown.What is the net force due to liquid on its curved surface? (neglect atmospheric pressure)

Options

A. `(2//3)piR^(2)hrhog`
B. `(1//3)piR^(2)hrhog`
C. `piR^(2)hrhog`
D. None

Answer

A

Explanation

upward force by liquid `=hrhogpiR^(2)-mg`
upward force by liquid `=hrhog.piR^(2)-(1)/(3)piR^(2)hrhog`
upward force by liquid `=(2)/(3) piR^(2)rhog`