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A dumbbell is placed in water of density...

A dumbbell is placed in water of density `rho`. It is observed that by attaching a mass `m` to the rod, the dumbbell floats with the rod horizontal on the surface of water and each sphere exactly half submerged as shown in the figure. The volume of the mass `m` is negligible. The value of length `l` is

A

`(d(Vrho-3m))/(2(Vrho-2m))`

B

`(d(Vrho-2m))/(2(Vrho-3m))`

C

`(d(Vrho+2m))/(2(Vrho-3m))`

D

`(d(Vrho-2m))/(2(Vrho+3m))`

Text Solution

Verified by Experts

The correct Answer is:
B

Taking torque about m.
`(B-Mg)(d-l)=(B-2Mg)l`
`((V)/(2)rhog-2Mg)(d-l)=((V)/(2)rhog-2Mg)l`
`((V)/(2)rhog-Mg)d-((V)/(2)rhog-Mg)l=((V)/(2)rhog-2Mg)l`
`((v)/(2)rhog-Mg)d=(Vrhog-3Mg)l`
`l=(((V)/(2)rhog-Mg))/((Vrhog-3Mg))" "impliesl=(Vrho-2M)/(2(Vrho-2M))`
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