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A cork of density 0.5gcm^(-3) floats on ...

A cork of density `0.5gcm^(-3)` floats on a calm swimming pool. The fraction of the cork's volume which is under water is

A

`0%`

B

`25%`

C

`10%`

D

`50%`

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AI Generated Solution

The correct Answer is:
To solve the problem of finding the fraction of the cork's volume that is submerged in water, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Data:** - Density of the cork, \( \rho_{\text{cork}} = 0.5 \, \text{g/cm}^3 \) - Density of water, \( \rho_{\text{water}} = 1 \, \text{g/cm}^3 \) (or \( 1000 \, \text{kg/m}^3 \)) 2. **Understand the Concept of Buoyancy:** - When an object floats, the weight of the object is equal to the buoyant force acting on it. This is described by Archimedes' principle. - The weight of the cork can be expressed as: \[ W_{\text{cork}} = \rho_{\text{cork}} \cdot V \cdot g \] where \( V \) is the total volume of the cork. 3. **Express the Buoyant Force:** - The buoyant force is equal to the weight of the water displaced by the submerged part of the cork: \[ F_b = \rho_{\text{water}} \cdot V_{\text{submerged}} \cdot g \] - Here, \( V_{\text{submerged}} \) is the volume of the cork that is submerged in water. 4. **Set Up the Equation:** - According to the equilibrium condition (weight of the cork = buoyant force): \[ \rho_{\text{cork}} \cdot V \cdot g = \rho_{\text{water}} \cdot V_{\text{submerged}} \cdot g \] - The \( g \) cancels out from both sides: \[ \rho_{\text{cork}} \cdot V = \rho_{\text{water}} \cdot V_{\text{submerged}} \] 5. **Express the Submerged Volume:** - Rearranging the equation gives: \[ V_{\text{submerged}} = \frac{\rho_{\text{cork}}}{\rho_{\text{water}}} \cdot V \] 6. **Substitute the Densities:** - Substitute the values of the densities: \[ V_{\text{submerged}} = \frac{0.5 \, \text{g/cm}^3}{1 \, \text{g/cm}^3} \cdot V = 0.5 \cdot V \] 7. **Calculate the Fraction Submerged:** - The fraction of the cork's volume that is submerged is: \[ \text{Fraction submerged} = \frac{V_{\text{submerged}}}{V} = \frac{0.5 \cdot V}{V} = 0.5 \] 8. **Convert to Percentage:** - To express this as a percentage: \[ \text{Percentage submerged} = 0.5 \times 100 = 50\% \] ### Final Answer: The fraction of the cork's volume which is under water is **50%**.

To solve the problem of finding the fraction of the cork's volume that is submerged in water, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Data:** - Density of the cork, \( \rho_{\text{cork}} = 0.5 \, \text{g/cm}^3 \) - Density of water, \( \rho_{\text{water}} = 1 \, \text{g/cm}^3 \) (or \( 1000 \, \text{kg/m}^3 \)) ...
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