Water is flowing steadily through a horizontal pipe of non-uniform cross-section. If the pressure of water is `4 xx 10^4 N//m^2` at a point where cross-section is `0.02 m^2` and velocity of flow is `2 m//s`. What is the pressure at a point where cross-section reduces to `0.01 m^2` ?
.

Options

A. `1.4xx10^(4)N//m^(2)`
B. `3.4xx10^(4)N//m^(2)`
C. `2.4xx10^(-4)N//m^(2)`
D. none of these

Answer

B

Explanation

`P_(1)+(1)/(2)rhov_(1)^(2)=P_(2)+(1)/(2)rhov_(2)^(2)" "....(1)`
From equation of continuty, `A_(1)v_(1)=A_(2)v_(2)`
`v_(2)=2v_(1)=8m//s" "....(2)`
From`(1) & (2)," " P_(2)=3.4xx10^(4)N//m^(2)`