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A cyclinderical vessel of cross-sectiona...

A cyclinderical vessel of cross-sectional area `1000cm^(2)`, fitted with a frictonless piston of mass `10kg`, and filled with water completely. A small hole of cross-sectional area `10mm^(2)` is opened at a point `50cm` deep from the lower surface of the piston. The velocity of efflux from the hole will be

A

`10.5m//s`

B

`3.4m//s`

C

`0.8m//s`

D

`0.2m//s`

Text Solution

AI Generated Solution

The correct Answer is:
To find the velocity of efflux from the hole in the cylindrical vessel, we can use Torricelli's theorem, which states that the speed of efflux of a fluid under the force of gravity through an orifice is given by the equation: \[ v = \sqrt{2gh} \] where: - \( v \) is the velocity of efflux, - \( g \) is the acceleration due to gravity (approximately \( 9.8 \, \text{m/s}^2 \)), - \( h \) is the height of the fluid column above the hole. ### Step-by-Step Solution: 1. **Identify the parameters:** - Cross-sectional area of the vessel, \( A = 1000 \, \text{cm}^2 = 0.1 \, \text{m}^2 \) - Mass of the piston, \( m = 10 \, \text{kg} \) - Depth of the hole from the lower surface of the piston, \( d = 50 \, \text{cm} = 0.5 \, \text{m} \) - Density of water, \( \rho = 1000 \, \text{kg/m}^3 \) - Acceleration due to gravity, \( g = 9.8 \, \text{m/s}^2 \) 2. **Calculate the pressure exerted by the piston:** \[ F = mg = 10 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 98 \, \text{N} \] The pressure \( P \) at the depth of the hole is given by: \[ P = \frac{F}{A} = \frac{98 \, \text{N}}{0.1 \, \text{m}^2} = 980 \, \text{Pa} \] 3. **Calculate the height of the water column above the hole:** The total height of the water column \( H \) is the height of the piston plus the height of the water above the hole. The height of the water column above the hole is: \[ h = H - d \] To find \( H \), we can use the relationship between pressure and height: \[ P = \rho g h \implies h = \frac{P}{\rho g} \] Substituting the values: \[ h = \frac{980 \, \text{Pa}}{1000 \, \text{kg/m}^3 \times 9.8 \, \text{m/s}^2} = 0.1 \, \text{m} = 10 \, \text{cm} \] Therefore, the height of the water column above the hole is: \[ H = d + h = 0.5 \, \text{m} + 0.1 \, \text{m} = 0.6 \, \text{m} \] 4. **Calculate the velocity of efflux:** Using Torricelli's theorem: \[ v = \sqrt{2gh} = \sqrt{2 \times 9.8 \, \text{m/s}^2 \times 0.6 \, \text{m}} = \sqrt{11.76} \approx 3.43 \, \text{m/s} \] 5. **Final result:** The velocity of efflux from the hole is approximately \( 3.4 \, \text{m/s} \). ### Conclusion: The velocity of efflux from the hole will be \( 3.4 \, \text{m/s} \).
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Knowledge Check

  • In a vessel containing water, a hole is made at a depth of 0.10 m from the free surface. What would be the velocity of efflux ?

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