A Newtonian fluid fills the clearance between a shaft and a sleeve. When a force of `800N` is applied to the shaft, parallel to the sleeve, the shaft attains a speed of `1.5cm//sec`. If a force of `2.4kN` is applied instead, the shaft would move with a speed of

Options

A. `1.5cm//sec`
B. `13.5cm//sec`
C. `4.5cm//sec`
D. None

Answer

C

Explanation

`Fpropv`
`(F_(2))/(F_(1))=(v_(2))/(v_(1))impliesv_(2)=((2400)/(800))xx1.5impliesv_(2)=4.5cm//s`