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Two drops of same radius are falling thr...

Two drops of same radius are falling through air with steady velocity of `v" "cm//s`. If the two drops coalesce, what would be the terminal velocity ?

A

`4v`

B

`(4)^(1//3)v`

C

`2v`

D

`64v`

Text Solution

Verified by Experts

The correct Answer is:
B
`V_("Big")=2V_("Small")" "impliesR_(B)=2^(1//3)R_(S)`
`v_(T)=(2)/(9)(piR^(2)(rho-sigma)g)/(eta)=v_(T)propR^(2)" "impliesv_(T(B))=2^(2//3)v_(T(S))impliesv_(T(B))=4^(1//3)v_(T(S))`
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Knowledge Check

  • Two drops of the same radius are falling through air with a steady velcoity of 5 cm s^(-1). If the two drops coalesce, the terminal velocity would be

    A
    `10 cm s^(-1)`
    B
    `2.5 cms^(-1)`
    C
    `5 (4)^(1//3) cm s^(-1)`
    D
    `5 (3)^(1//3) cm s^(-1)`

  • Two drops of same radius are falling through air with steady speed v. If the two drops coalesce, what would be the terminal speed –

    A
    4V
    B
    2V
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    D
    `2^(2//3)`V

  • Two water drops of the same radius are falling through air with a velocity 5cm/s. If the two drops coalesce to form one drop, the terminal velocity of the drop will be

    A
    10 cm/s
    B
    `5sqrt2cm//s`
    C
    2.5 cm/s
    D
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