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A beaker filled with water, is accelerat...

A beaker filled with water, is accelerated at a rate a `m/s^(2)` in forward direction. The surface of water shall make an angle

A

`tan^(-1)(a//g)` backwards

B

`tan^(-1)(a//g)` forwards

C

`cot^(-1)(g//a)` backwards

D

`cot^(-1)(g//a)` forwards

Text Solution

Verified by Experts

The correct Answer is:
A, C
`tan theta=(a)/(g)`
`theta = tan^(-1)a//g` backward
or
`theta=cot^(-1)g//a` backward
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