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A cubical block of wood of 10cm and mass...

A cubical block of wood of `10cm` and mass `0.92kg` floats on a tank of water with oil or rel. density `0.6`. Thickness of oil is `4cm` above water. When the block attains equilibrium with four of its sides edges verical:

A

`1cm` of it will be above the free surface of oil.

B

`5cm` of it will be under water.

C

`2cm` of it will be above the common surface of oil and water.

D

`8cm` of it will be under water.

Text Solution

Verified by Experts

The correct Answer is:
C, D
`W=B'+B`
`920g=x xx100xx0.6g+(10-x)xx100xxg`
`x=2cm`
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