`AB` is a part of circuit. Find the potential difference `V_(A) - V_(B)` if
a. current `I = 2 A` and is constant,
b. current `i = 2 A` and is increasing at the rate of `1 A s^(-1)`,
c. current `i = 2 A` and is decreasing at the rate of `1 A s^(-1)`,

Explanation

`L(di)/(dt)=1(di)/(dt)`
writing `KVL` from `A` to `B`
`V_(A)-1(di)/(dt)-5-2i=V_(B)`
(i)Put `i=2,(di)/(dt)=0`
`V_(A)-5-4=V_(B)`
`therefore V_(A)-V_(B)=9` volt
(ii)Put `i=2 (di)/(dt)=1, V_(A)-1-5-4=V_(B)` or `V_(A)-V_(B)=10 V_(0)`
(iii)Put `i=2 (di)/(dt)=-1, V_(A)+1-5-2xx2=V_(B)` or `V_(A)=8` volt .