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At t = 0, switch S is closed (shown in F...

At `t = 0`, switch `S` is closed (shown in Fig.). After a long time, suddenly the inductance of the inductor is made `eta` times lesser `(L//eta)` than its initial value. Find out current just after the operation.

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Using above result (note 4) `L_(1)i_(1)=L_(2)i_(2) rArr i_(2)=(etaepsilon)/R`
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