A straight wire with a resistance of `r` per unit length is bent to form an angle `2alpha`.A rod of the same wire perpendicular to the angle bisector (of `2alpha`) forms a closed triangular loop.This loop is placed in a uniform magnetic field of induction `B`.Calculate the current in the wires when the rod moves at a costant speed `V`.

Answer

A, B

Explanation

`epsilon=BV l,i=epsilon/R=(BVl)/[r[l+(2x)/(cos alpha)]]` where `cot alpha=x/(l+2)`