A superconducting loop of radius `R` has self inductance `L`.`A` uniform & constant magnetic field `B` is applied perpendicular to the plane of the loop.Initially current in this loop is zer.The loop is rotated about its diameter by `180^(@)`.Find the current in the loop after rotation.

Answer

B

Explanation

`epsilon=(dphi_(T))/(dt)=iR`
as `R=0` for super conducting loop
so `phi_(T)`=constant
`BpiR^(2)+0=-BpiR^(2)-LI`
`I=(2BpiR^(2))/L`