Two inductors `L_(1)` and `L_(2)` are connected in parallel and a time varying current flows as shown.
the ratio of current `i_(1)//i_(2)`

Options

A. `L_(1)//L_(2)`
B. `L_(2)//L_(1)`
C. `L_(1)^(2)/((L_(1)+L_(2))^(2)`
D. `L_(2)^(2)/((L_(1)+L_(2))^(2)`

Answer

B

Explanation

`L_(1)=(di_(1))/(dt)=L_(2)=(di_(2))/(dt)`
or `L_(1)di_(1)=L_(2)di_(2)` or `L_(1)i_(1)=L_(2)i_(2) rArr therefore i_(1)/i_(2)=L_(2)/L_(1)`