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In an LR circuit, current at t = 0 is 20...

In an `LR` circuit, current at `t = 0` is `20 A`. After `2 s` it reduces to `18 A`. The time constant of the circuit is :

A

In`(10/9)`

B

`2`

C

`2/("In"(10/9))`

D

`2 "In"(10/9)`

Text Solution

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The correct Answer is:
C
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