Two coils are at fixed location: When coil 1 has no corrent and the current in coil 2 increase at the rate of `15.0 A s^(-1)`, the emf in coil 1 is `25 mV`, when coil 2 has no current and coil 1 has a current of `3.6 A`, the flux linkange in coil 2 is

Options

A. `16 mWb`
B. `10 mWb`
C. `4.00 mWb`
D. `6.00 mWb`

Answer

D

Explanation

`EMF=|-M(dI)/(dt)|25xx10^(-3)=Mxx15` or `M=5/3xx10^(-3)H`
`phi=MI=5/3xx10^(-3)xx3.6=6.00 mWb`.