A `II`-shaped conductor is located in a uniform magnetic field perpendicular to the plane of the conductor and varying with time at the rate `(dB)/(dt)=0.10 T//s`.A conducting connectors starts moving with a constant acceleration `w=10 cm//s^(2)` along the parallel bars of the conductor.The length of the connector is equal to `l=20 cm`.Find the `emf` induced (in `mV`) in the loop `t=2.0 s` after the beginning of the motion.If at the moment `t=0` the loop area and the magnetic induction `(B)` are equal to zero.The self inductance of the loop is to be neglected.

Answer

A, B

Explanation

`epsilon=(dphi)/(dt)=A(dB)/(dt)+B(dA)/(dt)=(lx)(dB)/(dt)+B(Vl) rArrepsilon_(1)=3//2 omegal (dB)/(dt)t^(2)=12 mV`.