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An AC source producing emf epsilon = e...

An AC source producing `emf`
`epsilon = epsilon_0 [cos(100 pi s^(-1)) t + cos (500 pi s^(-1))t]`
is connected in series with a capacitor and a resistor. The steady-state current in the circuit is found to be
`I = i_1 cos [(100 pi s^(-1) t + varphi_1] + i_2 cos [(500 pi s^(-1))t +phi_2]`.

A

`i_(1) gt i_(2)`

B

`i_(1) = i_(2)`

C

`i_(1) lt i_(2)`

D

the information is insufficient to find the relation between `i_(1)` and `i_(2)`

Text Solution

Verified by Experts

Impedence `z` is given by `z=sqrt((1/(omegaC))^(2)+R^(2))` For higher `omega,z` will be lower so current will be higher
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