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A coil has an inductance of 22/pi H and ...

A coil has an inductance of `22/pi H` and is joined in series with a resistance of `220 Omega`.When an alternating `e.m.f` of `220 V` at `50 c.p.s` is applied to it.then the wattless component of the `rms` current in the circuit is

A

`5` ampere

B

`0.5` ampere

C

`0.7` ampere

D

`7` ampere

Text Solution

Verified by Experts

The correct Answer is:
B
Wattless current =`I_(rms)sinphi`
Where `tan phi=(omega L)/R=(2pifL)/R=1 rArr` and `I_(rms)=v_(rms)/z=v_(rms)/sqrt(R^(2)+(omegaL)^(2))=1/sqrt2`
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