The `rms` value of the saw-tooth voltage of peak value `V_(0)` from `t=0` to `t=2T` as shown in figure is `V_(0)/sqrtx`.Find the value of `x`.

Answer

3

Explanation

General equation of `V`
`V=V_(@)/(T//2)t-V_(0)=(2V_(0))/Tt-V_(0)`
`V_(rms)=[(underset(0)overset(T)intV^(2)dt)/T]^(1/2)=[(underset(0)overset(T)int((2V_(0))/Tt-V_(0))^(2)dt)/T]^(1/2)=V_(0)/sqrt3`
`x=3`