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A simple pendulum has some time period T...

A simple pendulum has some time period `T`. What will be the percentage change in its time period if its amplitude is decreased by `5%`

A

`6 %`

B

`3 %`

C

`1.5 %`

D

`0 %`

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The correct Answer is:
To solve the problem, we need to analyze the relationship between the time period of a simple pendulum and its amplitude. ### Step-by-Step Solution: 1. **Understanding the Time Period of a Simple Pendulum**: The time period \( T \) of a simple pendulum is given by the formula: \[ T = 2\pi \sqrt{\frac{L}{g}} \] where: - \( L \) is the length of the pendulum, - \( g \) is the acceleration due to gravity. 2. **Identifying the Independence from Amplitude**: From the formula, we can see that the time period \( T \) depends only on the length \( L \) and the gravitational acceleration \( g \). It does not depend on the amplitude of the pendulum's swing. 3. **Effect of Decreasing Amplitude**: The problem states that the amplitude of the pendulum is decreased by \( 5\% \). However, since the time period is independent of amplitude, this change in amplitude will not affect the time period. 4. **Calculating the Change in Time Period**: Since the time period remains constant regardless of the amplitude change, the change in time period \( \Delta T \) is: \[ \Delta T = 0 \] 5. **Finding the Percentage Change**: The percentage change in the time period can be calculated using the formula: \[ \text{Percentage Change} = \left(\frac{\Delta T}{T}\right) \times 100\% \] Substituting \( \Delta T = 0 \): \[ \text{Percentage Change} = \left(\frac{0}{T}\right) \times 100\% = 0\% \] ### Final Answer: The percentage change in the time period of the pendulum when its amplitude is decreased by \( 5\% \) is \( 0\% \). ---

To solve the problem, we need to analyze the relationship between the time period of a simple pendulum and its amplitude. ### Step-by-Step Solution: 1. **Understanding the Time Period of a Simple Pendulum**: The time period \( T \) of a simple pendulum is given by the formula: \[ T = 2\pi \sqrt{\frac{L}{g}} ...
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RESONANCE-SIMPLE HARMONIC MOTION -Exercise- 1, PART - II
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