A coin is placed on a horizontal platform which undergoes vertical simple harmonic motion of angular frequency `omega`. The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time :

Options

A. at the highest position of the platform
B. at the mean position of the platform
C. for an amplitude of `(g)/(omega^(2))`
D. for an amplitude of `(g^(2))/(omega^(2))`

Answer

A, C

Explanation

`Aomega^(2) = g`
`rArr A = g//omega^(2)`.