Two springs of force constants `k_(1)` and `k_(2)`, are connected to a mass m as shown. The frequency of oscillation of the mass is `f`. If both `k_(1)` and `k_(2)` are made four times their original values, the frequency of oscillation becomes

Options

A. `f//2`
B. `f//4`
C. `4f`
D. `2f`

Answer

D

Explanation

`f = (1)/(2pi)sqrt((k_(1) + k_(2))/(m)) , f_(max) = (1)/(2pi)sqrt((4k_(1) + 4k_(2))/(m)) = 2f`.