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The ration of the e//m (specific charge)...

The ration of the `e//m` (specific charge) values of an electron and an `alpha-"particle"` is

A

`2:1`

B

`1:1`

C

`1:2`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
`((e//m)_(e))/((e//m)_(alpha))=(e//m_(e))/(2e//4xx1836 m_(e))=3672/1`
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