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Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom . Calculate the ionisation energy of sodium in kJ `mol^(-1)`.

A

`494.65`

B

`400`

C

`247`

D

`600`

Text Solution

Verified by Experts

The correct Answer is:
A
I.E. of one sodium atom `=(hc)/(lambda)`
& I.E. of one mole `Na` atom `=(hc)/lambda N_(A)=(6.62xx10^(34)xx3xx10^(8)xx6.02xx10^(23))/(242xx10^(-9))=494.65 kJ.mol.`
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