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In H-atom if r1 is the radius fo first B...

In H-atom if `r1` is the radius fo first Bohr orbit de-Broglie wavelength of an elecrton in ` 3^(rd)` orbit is :

A

`3pi x`

B

`6pi x`

C

`(9x)/(2)`

D

`x/2`

Text Solution

Verified by Experts

The correct Answer is:
B
`r_(1)=0.529 Å`
`r_(3)=0.529xx(3)^(2)Å=9x` So, `lambda=(2pir)/(n)=(2pi(9x))/(3)=6 pi x`
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