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The latent heat of fusion of ice is 330 ...

The latent heat of fusion of ice is `330 J//g`. Calculate the number of photons of radiation of frequency `5xx10^(13) s^(-1)` to cause the melting of `1` mole of ice. Take `h=6.6xx10^(-34) J.S.` Express your answer as `X xx 10^(22)`, what is the value of 'X'

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The correct Answer is:
18
Heat required for melting `1` mole `(18 g)` of ice `=330xx18=5940 J`
Energy of one photon `=hv=6.6xx10^(-34)xx5xx10^(13)=33xx10^(-21) J`
`:.` total number of photons required `=5940/(33xx10^(-21))~~1.8xx10^(23)`
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