Total number of electrons having `n + l = 3` in `Cr(24)` atom in its ground state is.

Answer

8

Explanation

`sqrt(n(n+2))=4.9`
`:.` No. of unpaired electrons, `n=4`
`_(25)Mn : [Ar]4s^(2)3d^(5)`
for having `4` unpaired electrons, a Mn atom should lose `3` electrons (2 from `4s` and `1` from `3d`)
`:. a=+3`