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Calculate the work performed when 2 mole...

Calculate the work performed when `2` moles of hydrogen expand isothermally and reversibly at `25^(@)C` from `15` to `50` litres. (in cal)

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We have, `W= -2.303n RT "log"(V_(2))/(V_(1))= -2.303xx2xx2xx298xx"log"(50)/(15)= -1436` calories
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