A liquid of volume of `100 L` and at the external pressure of `10 atm-Lt` the liquid is confined inside an adiabatic bath. External pressure of the liquid is suddenly increased to `100 atm` and the liquid gets compressed by `1 L` against this pressure then find,
(i) Work (ii) `Delta U` (iii) `Delta H`

Explanation

Work done `= -100xx-1=100L. Atm`
`Delta q=0 Delta w=Delta U`
`rArr 100+Delta U`
`DeltaH=DeltaU+(P_(1)V_(2)-P_(1)V_(2))`
`=100=+(100xx99xx100xx10)`
`=100+100xx89=9000 "lit atm"`
`1L. atm=101.3"joule"`