Enthalpy of neutralization of `HCl` by `NaOH` is `-57.1 J//mol` and by `NH_(4)OH` is `-51.1 KJ//mol`. Calculate the enthalpy of dissociation of `NH_(4)OH`.

Explanation

To calculate the enthalpy of dissociation of \( NH_4OH \), we can use the given enthalpy of neutralization values for \( HCl \) with \( NaOH \) and \( NH_4OH \). Here’s a step-by-step solution:

### Step 1: Write the reactions for neutralization

1. The neutralization reaction of \( HCl \) with \( NaOH \):
\[ HCl + NaOH \rightarrow NaCl + H_2O \]
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