Using the bond enthalpy data given below, calculate the enthalpy change for the reaction
`C_(3)H_(4)(g)+H_(2)(g)rarrC_(2)H_(6)(g)`
`{:("Data":,"Bond",,"Bond enthalpy",),(,C-C,,336KJmol^(-1),),(,C=C,,606KJmol^(-1),),(,C-H,,410KJ mol^(-1),),(,H-H,,431KJ mol^(-1),):}`

Explanation

Diagrammatically, we represent the given reaction as follows:
`DeltaH_(r )=(4DeltaH_(C-H)+DeltaH_(C=C)+DeltaH_(H-H))-(6DeltaH_(C-H)+DeltaH_(C-C))`
`=(4xx410+606+431)-(6xx410+336)`
`=2677-2796`
`= -119 KJ//mol`.