A sample of 2 kg of helium (assumed ideal) is taken through the process ABC and another sample of 2 kg of the same gas is taken through the process ADC. Then, the temperature of the states A and B are : (Given `R = 8.3 J//"mol"-K)`:

Answer

C

Explanation

`(0.5xx10^(5))/(1.01xx10^(5))xx10xx10^(3)=(2xx1000)/(2)xx0.082T_(A)`
`(1)/(1.01)=0.082T_(A)`
`T_(A)=120.5K`
at constant volume
`(P_(A))/(T_(A))=(P_(6))/(T_(B))`
`T_(B)=(P_(B).T_(A))/(P_(A))=(10)/(5)xx120.5=241K`