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In an isothermal expansion of a gaseous ...

In an isothermal expansion of a gaseous sample the correct relation is (consider `w`(work) with sign according to new `IUPAC` convention)
[The reversible and irreversible processes are carried out between same initial and final states]

A

`W_(rev) gt W_(irrev)`

B

`W_(irrev) gt W_(rev)`

C

`q_(rev) lt q_(irrev)`

D

can not be predicted

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The correct Answer is:
B
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In an isothermical expansion of a gaseous sample the correct relation is (consider w (work) with sign according to IUPAC convention) [The reversible and irreversible procss are carried out between same initial and final states.]

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Identify the option which correctly represents set of true (T) false (F) statements: Statement :1 In an adiabatic free expansion, entropy of system remains constant. Statement-2: For every isothermal process, internal energy of the system remains contant. Statement-3: Molar enthalpy is an intensive parameter. Statement-4: For every reversible cyclic process, final state of surroundings is same as that of initial state of surroundings.

Four sample of ideal gas containig same moles and intially at same temperature and prcessure are subjected to four difference processes : (A) Isothermal reversible expansion (B) Isothermal irrversible expansion against final pressure (C ) Adiabatic reversible expansion (D) Adiabatic irreversible expansion against final pressure If in all the cases , final pressue is same then what will be the order of final temperture in the above cases.

A gaseous sample is generally allowed to do only expansion // compression type work against its surroundings The work done in case of an irreversible expansion ( in the intermediate stages of expansion // compression the states of gases are not defined). The work done can be calculated using dw= -P_(ext)dV while in case of reversible process the work done can be calculated using dw= -PdV where P is pressure of gas at some intermediate stages. Like for an isothermal reversible process. Since P=(nRT)/(V) , so w=intdW= - underset(v_(i))overset(v_(f))int(nRT)/(V).dV= -nRT ln(V_(f)/(V_(i))) Since dw= PdV so magnitude of work done can also be calculated by calculating the area under the PV curve of the reversible process in PV diagram. If four identical samples of an ideal gas initially at similar state (P_(0),V_(0),T_(0)) are allowed to expand to double their volumes by four different process. I: by isothermal irreversible process II: by reversible process having equation P^(2)V= constant III. by reversible adiabatic process IV. by irreversible adiabatic expansion against constant external pressure. Then, in the graph shown in the final state is represented by four different points then, the correct match can be

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