At `5xx10^(5)` bar pressure, density of diamond and graphite are `3 g//c c` and `2g//c c ` respectively, at certain temperature T. `(1 L. atm=100 J)`

Answer

5

Explanation

`{:(C_("graphite"),rarr,C_("diamond"),,),(1 "mole",,1"mole",,),(rho=2 g//cm^(3),,rho=3 g//cm^(3),,):}`
`V=(12)/(2)ml " "V=(12)/(3)ml`
`Delta H= Delta U+P Delta V`
`Delta U-Delta H= -P Delta V`
`= -5xx10^(5)((12)/(3)-(12)/(2))xx10^(-3)L.atm= -5xx10^(5)xx(12)/(6)xx10^(-1)J= 100 KJ//"mole"=10xx10^(4)J=100 KJ//"mole"`
`(Delta U-Delta H)/(20)=(100)/(20)=5` ans