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Calculate the bond energy of Cl-Cl bond ...

Calculate the bond energy of `Cl-Cl` bond from the following data:
`CH_(4)(g)+Cl_(2)(g)rarrCH_(3)Cl(g)+HCl(g), Delta H= -100.3 kJ`. Also the bond enthalpies of `C-H, C-Cl,H-Cl` bonds are `413,326` and `431 kJ mol^(-1)` respectively.

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To calculate the bond energy of the Cl-Cl bond from the given reaction data, we will follow these steps: ### Step 1: Write the reaction and the given data The reaction provided is: \[ \text{CH}_4(g) + \text{Cl}_2(g) \rightarrow \text{CH}_3\text{Cl}(g) + \text{HCl}(g) \] The enthalpy change (\(\Delta H\)) for this reaction is given as: \[ \Delta H = -100.3 \, \text{kJ} \] ### Step 2: Identify the bonds in reactants and products In the reactants: - CH₄ has 4 C-H bonds. - Cl₂ has 1 Cl-Cl bond. In the products: - CH₃Cl has 3 C-H bonds and 1 C-Cl bond. - HCl has 1 H-Cl bond. ### Step 3: Write the bond energy equation Using the formula for bond dissociation enthalpy: \[ \Delta H = \text{(Bonds broken)} - \text{(Bonds formed)} \] We can express this as: \[ \Delta H = [4 \times \text{(C-H)} + 1 \times \text{(Cl-Cl)}] - [3 \times \text{(C-H)} + 1 \times \text{(C-Cl)} + 1 \times \text{(H-Cl)}] \] ### Step 4: Substitute the known bond energies The bond energies are given as: - C-H bond = 413 kJ/mol - C-Cl bond = 326 kJ/mol - H-Cl bond = 431 kJ/mol Substituting these values into the equation: \[ -100.3 = [4 \times 413 + 1 \times X] - [3 \times 413 + 1 \times 326 + 1 \times 431] \] ### Step 5: Calculate the left side of the equation Calculating the left side: - Bonds broken: \[ 4 \times 413 = 1652 \, \text{kJ} \] - Bonds formed: \[ 3 \times 413 = 1239 \, \text{kJ} \] \[ 1239 + 326 + 431 = 1996 \, \text{kJ} \] ### Step 6: Substitute and simplify the equation Now substituting these values back into the equation: \[ -100.3 = [1652 + X] - 1996 \] This simplifies to: \[ -100.3 = 1652 + X - 1996 \] \[ -100.3 = X - 344 \] ### Step 7: Solve for X (the bond energy of Cl-Cl) Rearranging gives: \[ X = -100.3 + 344 \] Calculating this: \[ X = 243.7 \, \text{kJ/mol} \] ### Final Answer The bond energy of the Cl-Cl bond is: \[ \boxed{243.7 \, \text{kJ/mol}} \]

To calculate the bond energy of the Cl-Cl bond from the given reaction data, we will follow these steps: ### Step 1: Write the reaction and the given data The reaction provided is: \[ \text{CH}_4(g) + \text{Cl}_2(g) \rightarrow \text{CH}_3\text{Cl}(g) + \text{HCl}(g) \] The enthalpy change (\(\Delta H\)) for this reaction is given as: \[ \Delta H = -100.3 \, \text{kJ} \] ...
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