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10 mL of each 1 mL HCl and 1M H(2)SO(4) ...

`10 mL` of each `1 mL HCl` and `1M H_(2)SO_(4)` are neutralized by `1 M NaOH` solution that liberate the heat of `a` & `b kJ//` equivalent respectively. What is relation between `a` and `b`

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The correct Answer is:
`2a=b`
`H_(2)SO_(4)rarr`diprotic acid and `HCl rarr`mono protic acid.
So, `H_(2)SO_(4)` will release double amount of that than `HCl`.
So, `2a=b`
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