One mole of an ideal diatomic gas `(C_(v) =5 cal)` was transformed from initial `25^(@)` and `1 L` to the state when temperature is `100^(@)` C and volume `10` L. The entropy change of the process can be expressed as (`R=2` calories /mol/K)

Options

A. `3 "In" (298)/(373) + 2 "In" 10`
B. `5 "In" (373)/(298) + 2 "In"10`
C. `7 "In" (373)/(298) + 2 "In" (1)/(10)`
D. `5 "In" (373)/(298) + 2 "In"( 1)/(10)`

Answer

B

Explanation

`DeltaS = nC_(v) "In" ((T_(f))/(T_(i))) + nR "In" ((V_(f))/(V_(i))) = (5)/(2) xx 2 "In" (373)/(298) + 2 "In"10`