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We have taken a saturated solution of Ag...

We have taken a saturated solution of `AgBr.K_(sp)` of `AgBr` is `12xx10^(-14)`. If `10^(-7)` mole of `AgNO_(3)` are added to 1 mitre of this solutio then the conductivity of this solution in terms of `10^(-7)Sm^(-1)` units will be [given `lamda((Ag^(+)))^(@)=4xx10^(-3)Sm^(2)mol^(-1)lamda_((Br^(-)))^(@)=6xx10^(-3)Sm^(2)mol^(-1). lamda_((NO_(3)^(-)))^(@)=5xx10^(-3)Smmol^(-1))`
(A). 39
(B). 55
(C). 15
(D). 41

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We have taken a saturated solution of AgBr,K_(sp) of AgBr is 12xx10^(-14) . If 10^(-7) "mole" of AgNO_(3) are added to 1 litre of this solution then the conductivity of this solution in terms of 10^(-7) Sm^(-1) units will be: [Given: lambda_((Ag^(+)))^(@)=4xx10^(-3)Sm^(2)"mol"^(-1),lambda_((Br^(-)))^(@)=6xx10^(-3) S m^(2) "mol"^(-1),lambda_((NO_(3)^(-)))^(@)=5xx10^(-3)Sm^(2) "mol"^(-1) ]

We have taken a saturated solution of AgBr , whose K_(sp) is 12xx10^(-14). If 10^(-7)M of AgNO_(3) are added to 1L of this solutino, find the conductivity ( specific conductance ) of the solution in terms of 10^(-7)S m^(-1) units. Given : lambda^(@)._((Ag^(o+)))=6xx10^(-3)S m^(2) mol^(-1) lambda^(@)._((Br^(c-)))=8xx10^(-3)S m^(2)mol^(-1) lambda^(@)._((NO_(3)^(C-)))=7XX10^(-3)S m^(2) mol^(-1)

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