In a cell that untillizes the reaction ,
`Zn_((s)) + 2 H_((aq))^+ rarr Zn_((aq.))^(2+) + H_(2 (g) )`, adedition of ` H_2 SO_4` to cathode compartment will :

Options

A. lower the E and shift equilibrium to the left.
B. lower the E and shift the equilibrium to the right
C. increase the E and shift the equilibrium to the right.
D. increase the E and shift the equilibrium to the left.

Answer

C

Explanation

`Zn+2H_((aq))^(+)toZn^(2+)(aq)+H_(2)(g)`
`E=E^(@)-(0.0591)/(2)log(([Zn^(2+)]pH_(2))/([H^(+)]^(2)))`
Adding `H_(2)SO_(4)` means increasing `H^(+)` and therefore `E_(cell)` will increase and reaction will shift to forward direction.