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At 25^(@)C, {:(Ag+I^(-)rarr,AgI+e,,E^(@)...

At `25^(@)C, {:(Ag+I^(-)rarr,AgI+e,,E^(@) =0.152V),(Agrarr,Ag.^(+)+e,,E^(@) =- 0.80V):}`
The `log K_(sp)` of `AgI` is: `((2.303RT)/(F)=0.059)`

A

`-8.12`

B

`+8.612`

C

`-37.83`

D

`-16.13`

Text Solution

Verified by Experts

The correct Answer is:
D
`0.152=-0.8-(0.059)/(1)logK_(SP):logK_(SP)=-16.11`
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