A sample of charcoal weighing `6 g` was brought into contact with a gas contained in a vessel of one litre capacity at `27^(@)C`. The pressure of the gas was found to fall from `700` to `400` mm. Calculate the volume of the gas (reduced to STP) that is adsorbent under the condition of the experiment `("density of charcoal sample is" 1.5 g cm^(3))`.

Explanation

The adsorption is taking place in a closed vessel hence if pressure falls is correspondingly increase in volume constant, excess of the volume of the gas would be adsorbed.
`P_(1)V_(1)=P_(2)V_(2)`
`V_(2)=P_(1) V_(1)/P_(2)=700xx1000/40=1750 mL`
Actual volume of the flask `=1000- "volume of charcoal"=1000-6.00/1.50=996 mL`
volume of the gas adsorbed `=1750-996=754 mL`
Volume of the gas adsorbed per gram at STP `("U sing" (P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2)))`
`=(125.67xx400xx273)/(300xx760)=60.19 mL`