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The pressure inside two soap bubbles is ...

The pressure inside two soap bubbles is 1.01 and 1.02 atmosphere. The ration of their respective volumes is

A

`4 :1`

B

`2 :1`

C

`0.8 :1`

D

`8 :1`

Text Solution

Verified by Experts

The correct Answer is:
D
`P_("in") =P_0 +(4T)/(R_1)`
`1.01 = 1 +(4T)/(R_1)`
` 0.01 =(4T)/(R_1)`
` 1/2 = (R _2)/(R_1)`
` (V_1)/(V_2)=(8)/(1)`
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