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Of the species, NO, NO^(+), NO^(2+) and ...

Of the species, `NO, NO^(+), NO^(2+) and NO^(-)`, the one with minimum bond strength is :

A

`NO^(-)`

B

`NO^(+)`

C

`NO^(2+)`

D

`NO`

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The correct Answer is:
To determine which of the species \( NO, NO^+, NO^{2+}, \) and \( NO^- \) has the minimum bond strength, we need to analyze their bond orders. The bond strength is inversely proportional to the bond length, and the bond length is inversely proportional to the bond order. Therefore, a lower bond order indicates a weaker bond. ### Step-by-Step Solution: 1. **Identify the number of electrons in each species:** - For \( NO \): Nitrogen (N) has 7 electrons, and Oxygen (O) has 8 electrons. Therefore, the total number of electrons = \( 7 + 8 = 15 \). - For \( NO^+ \): This species has one less electron due to the positive charge. Thus, total electrons = \( 15 - 1 = 14 \). - For \( NO^{2+} \): This species has two less electrons due to the two positive charges. Thus, total electrons = \( 15 - 2 = 13 \). - For \( NO^- \): This species has one extra electron due to the negative charge. Thus, total electrons = \( 15 + 1 = 16 \). 2. **Determine the bond order for each species:** - The bond order can be determined using the following: - 15 electrons correspond to a bond order of 2.5. - 14 electrons correspond to a bond order of 3. - 13 electrons correspond to a bond order of 2. - 16 electrons correspond to a bond order of 2. - Therefore, we have: - Bond order of \( NO = 2.5 \) - Bond order of \( NO^+ = 3 \) - Bond order of \( NO^{2+} = 2 \) - Bond order of \( NO^- = 2 \) 3. **Compare the bond orders:** - \( NO^+ \) has the highest bond order (3), indicating the strongest bond. - \( NO \) has a bond order of 2.5. - \( NO^{2+} \) and \( NO^- \) both have a bond order of 2. 4. **Identify the species with the minimum bond strength:** - Since \( NO^{2+} \) and \( NO^- \) both have the lowest bond order of 2, they have the minimum bond strength. However, since they are equal, we can conclude that either \( NO^{2+} \) or \( NO^- \) has the minimum bond strength. ### Conclusion: The species with minimum bond strength among \( NO, NO^+, NO^{2+}, \) and \( NO^- \) is \( NO^{2+} \) or \( NO^- \) (both have the same bond order).

To determine which of the species \( NO, NO^+, NO^{2+}, \) and \( NO^- \) has the minimum bond strength, we need to analyze their bond orders. The bond strength is inversely proportional to the bond length, and the bond length is inversely proportional to the bond order. Therefore, a lower bond order indicates a weaker bond. ### Step-by-Step Solution: 1. **Identify the number of electrons in each species:** - For \( NO \): Nitrogen (N) has 7 electrons, and Oxygen (O) has 8 electrons. Therefore, the total number of electrons = \( 7 + 8 = 15 \). - For \( NO^+ \): This species has one less electron due to the positive charge. Thus, total electrons = \( 15 - 1 = 14 \). - For \( NO^{2+} \): This species has two less electrons due to the two positive charges. Thus, total electrons = \( 15 - 2 = 13 \). ...
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