Resultant of two forces when angle between them is `60^(@)` is 6 Newton and if angle between forces increased to `120^(@)` then resultant becomes `sqrt(14N)`, then what will be resultant of these two forces when they will per pendicular to each other

Options

A. 10N
B. 5N
C. `5sqrt(2)N`
D. 4N

Answer

C

Explanation

`F_(1)^(2)+F_(2)^(2)+F_(1)F_(2)=36`
`F_(1)^(2)+F_(2)^(2)-F_(1)F_(2)=14`
`F=sqrt(F_(1)^(2)+F_(2)^(2))=sqrt(50)=5sqrt(2)`