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Young modulus of steel is 3 xx 10^(11) N...

Young modulus of steel is `3 xx 10^(11) N//m^(2)`. When expressed in C.G.S. unit of `"Dyne"//cm^(2)` it will be equal to

A

`9xx10^(12) "Dyne"//cm^(2)`

B

`9xx10^(11) "Dyne"//cm^(2)`

C

`3xx10^(12) "Dyne"//cm^(2)`

D

`3xx10^(11) "Dyne"//cm^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`n_(1)u_(1)=n_(2)u_(2)`
`3xx10^(11)[M_(1)L_(1)^(-1)T_(1)^(-2)]=n_(2)[M_(2)L_(2)^(-1)T_(2)^(-2)]`
`n_(2)=(3xx10^(11))[((M_(1))/(M_(2)))^(1)((L_(1))/(L_(2)))^(-1)((T_(1))/(T_(2)))^(-2)]`
`n_(2)=(3xx10^(11))[((kg)/(gm))^(1)((m)/(cm))^(-1)((1sec)/(1sec))^(-2)]`
`n_(2)=(3xx10^(11))[((1000gm)/(gm))^(1)((1000cm)/(cm))^(-1)((1sec)/(1sec))^(-2)]`
`n_(2)=(3xx10^(11))[10]=3xx10^(12)"Dyne"//cm^(2)`
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