A body A is dropped from a height h above the ground. At the same time another body B (at a horizontal' distance d from the line of fall of A) is fired from the ground at an angle `alpha` to the horizontal. If the two bodies collide at the highest point of the trajectory of B the angle of projection is given by

Options

A. `alpha=tan^(-1)((d)/(h))`
B. `alpha=sin^(-1)((h)/(d))`
C. `alpha=tan^(-1)((h)/(d))`
D. `alpha=cos^(-1)((h)/(d))`

Answer

C

Explanation

`(u^(2)sin2 alpha)/(g)=2d" "......(i)`
`implies h=(u^(2)sin^(2)alpha)/(g)" ".......(ii)`
`(h)/(d)=tanalpha implies alpha=tan^(-1)((h)/(d))`