An aeroplane is flying vertically upwards. When it is at a height of `1000 m` above the ground and moving at a speed of `367 m//s`., a shot is fired at it with a speed of 567 `ms^(-1)` from a point directly below it. What should be the acceleration of aeroplane so that it may escape from being hit?

Options

A. `gt5 m//s^(2)`
B. `gt10 m//s^(2)`
C. `lt10 m//s^(2)`
D. Not possible

Answer

B

Explanation

`567t-5t^(2)=1000+367t+(A)/(2)t^(2)`
`((A)/(2)+5)t^(2)-200t+1000=0`
For not escape `A le 10m//s^(2)`
For escape `A gt 10 m//s^(2)`