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A particle is resting over a smooth horizontal floor AT t = 0, a horizontal force starts acting on it. Magnitude of the force increases with time F = kt, where k is a constant. The two curves are drawn for this particle as shown

A

Curve-1 shows acceleration versus time

B

Curve-2 shows velocity versus time

C

Curve-2 shows velocity versus acceleration

D

Curve-1 shows velocity versus acceleration

Text Solution

Verified by Experts

The correct Answer is:
A, B, C

`F = kt implies a=(kt)/(m), " "v = (kt^(2))/(2m)=(k)/(2m)((ma)/(k))^(2)=(ma^(2))/(2k)`
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